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9g^2+2g-11=0
a = 9; b = 2; c = -11;
Δ = b2-4ac
Δ = 22-4·9·(-11)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{400}=20$$g_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-20}{2*9}=\frac{-22}{18} =-1+2/9 $$g_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+20}{2*9}=\frac{18}{18} =1 $
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